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If the system of equations $a x + y = 3, x + 2 y = 3$ , $3 x + 4 y = 7$ is consistent, then value of a is given by

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Correct option is A

Solving x+2y=3,3x+4y=7, we get x=1, y=1∴ a+1=3⇒a=2

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If the system of equations ax + y= 3, x + 2y = 3, 3x + 4y = 7 is consistent, then value of a is given by

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If the system of equations $a x + y = 3, x + 2 y = 3$ , $3 x + 4 y = 7$ is consistent, then value of a is given by