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If the system of equations $a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7$ is consistent , then value of a is given by

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Correct option is A

2x+4y=63x+4y=7− − −−x=−1Now x+2y=3⇒2y=2⇒y=1 ∴ax+y=3 ⇒a=3-1=2 ⇒a=2

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If the system of equations ax+y=3,x+2y=3,3x+4y=7is consistent , then value of a is given by

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If the system of equations $a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7$ is consistent , then value of a is given by