If the system of equations x+2y−3z=1,(p+2)z=3,(2p+1)y+z=2 is inconsistent, then the value of 2020500p=

If p≠−2,−12 then z=3p+2andy=1p+2Corresponding to this value we can get ‘x’If p=−12, we get z=2, thus we get infinite no. of values of xand y.Thus, p=−2, the system is inconsistent.∴2020500p=2020500-2=-8.08