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If the system of equations ax+y+z=0,x+by+z=0,x+y+cz=0,a,b,c1  has a non trivial solution ( non-zero solution) , then 11a+11b+11c= 

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detailed solution

Correct option is A

Given system of equations has a nontrivial solution   ⇒ coefficient matrix is singular⇒a111b111c=⇒abc−1−1c−1+11−b=0⇒abc−a−c+1+1−b=0⇒abc=a+b+c−211−a+11−b+11−c=(1−b)(1−c)+(1−a)(1−c)+(1−a)(1−b)(1−a)(1−b)(1−c)⇒3−2(a+b+c)+bc+ac+ab1−(a+b+c)+ab+bc+ca−abc=3−2(a+b+c)+bc+ca+ab1−(a+b+c)+ab+bc+ca−(a+b+c−2)=1


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If the system of equations, ax+by+cz=0 , bx+cy+az=0  and cx+ay+bz=0  have non trivial solution, then


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