Q.
If the system of equations ax+y+z=0, x+by+z=0 and x+y+cz=0 (a, b, c≠1) has a non-trivial solution, then the value of 11−a+11−b+11−c is
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a
−1
b
0
c
1
d
None of these
answer is C.
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Detailed Solution
For given homogenous equations to have non-zero solution, |a111b111c|=0 |a111−ab−101−a0c−1|=0⇒ a(b−1)(c−1)−(1−a)(c−1)−(1−a)(b−1)=0Dividing by (1−a)(1−b)(1−c), we get a1−a+11−c+11−b=0⇒ 11−a+11−b+11−c=1
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