If the system of linear equations 4x+ky+2z=0,kx+4y+z=0,2x+2y+z=0 possess a non-zero solution, so that k has two values k1,k2then k13+k2333=

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.6667.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

System has non-zero solution⇒Δ=0 ⇒4k2k41221=0 ⇒44-2-kk-2+22k-8=0 ⇒k2−6k+8=0 ⇒k=2,4 Let k1=2 and k2=4. Then k13+k2333=8+6427=7227=2.6667

Watch 3-min video & get full concept clarity