If the system of linear equations  x−2y+kz=1,2x+y+z=2,3x−y−kz=3 has a solution  x,y,x,z≠o , then  x,y lies on the straight line whose equation is

Given system of linear equations x−2y+kz=1----12x+y+z=2----2 And  3x−y−kz=3----3 Has a solution (x,y,z),z≠0On adding Eqs. (i) and (iii), we get x+2y+kz+3x−y−kz=1+34x−3y=4⇒4x−3y−4=0This is the required equation of the straight line in which point x,y lies .