Q.
If the system of linear equations x+y+z=a, x−y+bz=2,2x+3y−z=1 has infinitely many solutions, then b−5a=
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answer is 3.
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Detailed Solution
Augmented matrix =111a1-1b223-11 ~R2→R2−R1R3→R3 −2R1 111a0-2b-12-a01-31-2a ~R3→2R3 +R2 111a0-2b-12-a01b-74-5aGiven system has infinitely many solutions⇒b−7=0, 4−5a=0b=7, a=45b−5a= 7−5×45 = 7−4=3
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