If the system of linear equations $$x+y+z=5$$, $$x+2y+2z=6$$, $$x+3y+$$λ$$z=uhas$$ infinitely many solutions, then the value of λ$$+u$$ is

Question

If the system of linear equations  $$x+y+z=5$$,   $$x+2y+2z=6$$,   $$x+3y+$$λ$$z=uhas$$ infinitely many solutions, then the value of λ$$+u$$ is

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Augments matrix $$=1115122613$$λμ                                      $$=R2$$→$$R2-R1$$, $$R3$$→$$R3-R1$$ $$1116011102$$λ$$-1$$μ$$-5$$                                         $$=R3$$→$$R3-2R1$$ $$1115011100$$λ$$-3$$μ$$-7Given$$ system has infinitely many solutions⇒λ−$$3=0$$,    u−$$7=0$$⇒λ$$=3$$,    $$u=7$$⇒λ$$+$$ u  $$=$$  $$3+7=10$$

If the system of linear equations $x + y + z = 5, x + 2 y + 2 z = 6, x + 3 y + λ z = u$ has infinitely many solutions, then the value of $λ + u$ is

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If the system of linear equations x+y+z=5, x+2y+2z=6, x+3y+λz=uhas infinitely many solutions, then the value of λ+u is

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If the system of linear equations $x + y + z = 5, x + 2 y + 2 z = 6, x + 3 y + λ z = u$ has infinitely many solutions, then the value of $λ + u$ is