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Q.

If the system of linear equations  2x+2y+3z=a,  3x−y+5z=b,x−3y+2z=c where a,b,c non – zero real numbers, has more than one solution, Then

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a

b−c−a=0

b

a+b+c=0

c

b+c−a=0

d

b−c+a=0

answer is A.

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Detailed Solution

2x+2y+3z=a→(1),3x−y+5z=b→(2),  x−3y+2z=c→(3)(1) + (3)⇒3x−y+5z=a+cb=a+c
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