If the system of linear equations,x+y+z=6x+2y+3z=103x+2y+λz=μhas more than two solutions, then μ-λ2 is equal to ______________

x+y+z=6_____(1)x+2y+3z=10_____(2)3x+2y+λz=μ_____(3)from (1) and (2)If  z=0⇒x+y=6and  x+2y=10⇒y=4,x=2 ∴2,4,0 is a solution of the given system                   If y=0⇒x+z=6 and x+3z=10        ⇒z=2   andx=4⇒4,0,2 is a solution of the given system   Now equation (3) must satisfy the solutions 2,4,0and  4,0,2.⇒μ=14, and 12+2λ=μ⇒λ=1 ∴μ−λ2=14−1= 13