Q.

If Tn denotes the nth term of the series 2+3+6+11+18+… then T50 is

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Detailed Solution

Let, S=2+3+6+11+18+…+Tnor S=2+3+6+11+…+TnOn subtracting,  we get 0=2+1+3+5+7+…−Tn⇒ Tn=2+[1+3+5+…(n−1) term ]=2+n−12[2+(n−1−1)2] Fn=2+(n−1)2∴ T50=2+(50−1)2=492+2
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If Tn denotes the nth term of the series 2+3+6+11+18+… then T50 is