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Questions  

If Tanθ+Secθ=3, then the principal value of θ+π6 is

a
π3
b
π4
c
2π3
d
π2

detailed solution

Correct option is A

tanθ+secθ=3⇒sinθ+1=3cosθ⇒3cosθ−sinθ=1⇒32cosθ−12sinθ=12⇒cosθcosπ6−sinθsinπ6=12⇒cosθ+π6=12∴ PS of θ+π6=π3

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