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If $θ = T a n^{- 1} a, ϕ = T a n^{- 1} b$ and $a b = - 1$ , then $θ - ϕ$ is equal to:

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π4

π2

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detailed solution

Correct option is C

Tan(θ−Φ)=Tanθ−TanΦ1+TanθTanΦ=a−b1−1=∞θ−Φ=π2

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If θ=Tan−1a,ϕ=Tan−1band ab=-1, then θ−ϕis equal to:

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If $θ = T a n^{- 1} a, ϕ = T a n^{- 1} b$ and $a b = - 1$ , then $θ - ϕ$ is equal to: