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Questions  

If  3Tan4α10Tan2α+3=0 then principal values of ‘α’ are

a
±450,±360
b
±300,±600
c
±750,±360
d
±600,±150

detailed solution

Correct option is B

3tan4α−10tan2α+3=0⇒3tan4α−9tan2α−tan2α+3=0⇒(3tan2α−1)(tan2α−3)=0⇒tan2α=13=132;tan2α=3=(3)2∴α=±300,±600

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