If 3Tan4α−10Tan2α+3=0 then principal values of ‘α’ are
±450,±360
±300,±600
±750,±360
±600,±150
3tan4α−10tan2α+3=0
⇒3tan4α−9tan2α−tan2α+3=0
⇒(3tan2α−1)(tan2α−3)=0
⇒tan2α=13=132;tan2α=3=(3)2
∴α=±300,±600