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If $T a n^{- 1} x, T a n^{- 1} y, T a n^{- 1} z$ are in A.P then $\frac{2 y}{1 - y^{2}} =$

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x−z1+xz

x+z

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Correct option is D

Tan-1x, Tan-1y, Tan-1z are in A.P.⇒2Tan−1y=Tan−1x+Tan−1z⇒Tan−12y1−y2=Tan−1x+z1−xz⇒2y1−y2=x+z1−xz

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If Tan−1x,Tan−1y,Tan−1z are in A.P then 2y1−y2=

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Ready to Test Your Skills?

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If $T a n^{- 1} x, T a n^{- 1} y, T a n^{- 1} z$ are in A.P then $\frac{2 y}{1 - y^{2}} =$