If 2tanâ¡(Ï/3)cosâ¡(2Ïx)=3, the general solution of the equation is
2nϱÏ3
n±13
n±16
n±12 (nâI)
2Ã3cosâ¡(2Ïx)=3âcosâ¡(2Ïx)=1/2=cosâ¡(2nϱÏ/3)âx=n±1/6.