If tanâ¡Î¸, 2tanâ¡Î¸+2, 3tanâ¡Î¸+3 are in G.P., then the value of 7â5cotâ¡Î¸9â4sec2â¡Î¸â1 is
125
â 3328
33100
1213
tanâ¡Î¸(3tanâ¡Î¸+3)=(2+2tanâ¡Î¸)2â(1+tanâ¡Î¸)(4+tanâ¡Î¸)=0âtanâ¡Î¸=â4 as tanâ¡Î¸â â1 So 7â5cotâ¡Î¸9â4sec2â¡Î¸â1=7+5/49+16=33100