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If $\tan (A + B) = p, \tan (A - B) = q$ then $\cot 2 B =$

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Correct option is A

2B=(A+B)-(A-B) Apply cot on both sides cot2B=cot(A+B)cot(A-B)+1cot(A-B)-cot(A+B)=1p1q+11q−1q=1+pqp−q

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If tan(A+B)=p,tan(A−B)=q then cot2B=

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Ready to Test Your Skills?

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If $\tan (A + B) = p, \tan (A - B) = q$ then $\cot 2 B =$