If tan ⁡(A−B)=1 and sec⁡ (A+B)=2/3, then the smallest positive values of A and B, respectively, are

tan⁡ (A−B)=1⇒A−B=n1π+π4 or A−B=π4,3π4,−3π4,…sec⁡ (A+B)=23⇒A+B=2n2π±π6 or A+B=π6,11π6,…For the least positive values of A and B, we haveA+B=11π6,A−B=π4⇒B=19π24,A=25π24