If tan(A−B)=1 and sec(A+B)=2/3 then the smallest positive values of ,A and B, respectively, are
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a
25π24,19π24
b
19π24,25π24
c
31π24,13π24
d
13π24,31π24
answer is A.
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Detailed Solution
tan(A−B)=1⇒ A−B=n1π+π4 or A−B=π4,3π4,−3π4,… sec(A+B)=23⇒ A+B=2n2π±π6 or A+B=π6,11π6,…For the least positive values of ,A and B, we have A+B=11π6, A−B=π4⇒ B=19π24, A=25π24