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If $A = \tan 1, B = \tan 2, C = \tan 3$ Then descending order of A, B, C

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Correct option is C

A=tan57°, B=tan114°( approximately )and C=tan171°⇒A=tan57° ,B=-tan66°,C=-tan9°⇒A>C>Bsince tanx is increasing in -π2,π2

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If A=tan1, B=tan2, C=tan3 Then descending order of A, B, C

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If $A = \tan 1, B = \tan 2, C = \tan 3$ Then descending order of A, B, C