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a
a
b
b
c
ab
d
ba
answer is B.
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Detailed Solution
write cos2θ,sin2θ in terms of tanθcos2θ=1-tan2θ1+tan2θ sinθ=2tanθ1+tan2θ b cos2θ +a sin2θ=b1-a2b21+a2b2+a2ab1+a2b2 =bb2-a2b2+a2+2a2ba2+b2 =bb2+a2b2+a2=b