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If $\tan θ = \frac{a}{b},$ then $b \cos 2 θ + a \sin 2 θ$ is equal to

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detailed solution

Correct option is B

write cos2θ,sin2θ in terms of tanθcos2θ=1-tan2θ1+tan2θ sinθ=2tanθ1+tan2θ b cos2θ +a sin2θ=b1-a2b21+a2b2+a2ab1+a2b2 =bb2-a2b2+a2+2a2ba2+b2 =bb2+a2b2+a2=b

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If tanθ=ab, then bcos2θ+asin2θ is equal to

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If $\tan θ = \frac{a}{b},$ then $b \cos 2 θ + a \sin 2 θ$ is equal to