If tan(θ/2)=cosecθ−sinθ, then cos2(θ/2) is equal to
sin18∘sin18∘
cos36∘
sin36∘
cos18∘
sin(θ/2)cos(θ/2)=1−sin2θsinθ⇒2sin2(θ/2)=cos2θ⇒cos2θ+cosθ−1=0⇒cosθ=−1±1+42=−1±52
But cosθ≠−1−52 so cosθ=5−12
⇒2cos2(θ/2)=5−12+1=5+12⇒cos2(θ/2)=5+14=cos368.