If tanθ=34 and θ is not in the first quadrant, then sin(π2+θ)−cot(π−θ)tan(3π2−θ)−cos(3π2+θ)=

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629

829

729

−829

answer is B.

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Detailed Solution

Since θ∈Q3 , we have sin(π2+θ)−cot(π−θ)tan(3π2−θ)−cos(3π2+θ)=+cosθ+cotθcotθ−sinθ=+(−45)+4343−(−35) = 829

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