First slide

Trigonometric equations

Question

If $\tan p θ = \tan q θ$ then the values of $θ$ form an $A . P .$ with common difference

Moderate

A

$π / (p + q)$
B

$π / p$
C

$π / q$
D

$π / (p - q)$

Solution

$p θ = n π + q θ \Rightarrow (p - q) θ = n π \Rightarrow θ = \frac{n π}{p - q}$
So the values of $θ$ form an A.P. with common difference $π / (p - q)$

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