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If $\tan p θ = \tan q θ$ then the values of $θ$ form an $A . P .$ with common difference

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π/(p+q)

π/p

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detailed solution

Correct option is D

pθ=nπ+qθ⇒(p−q)θ=nπ⇒θ=nπp−qSo the values of θform an A.P. with common difference π/(p – q)

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If tan⁡pθ=tan⁡qθ then the values of θ form an A.P. with common difference

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If $\tan p θ = \tan q θ$ then the values of $θ$ form an $A . P .$ with common difference