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$If θ = \tan^{- 1} a, ϕ = \tan^{- 1} b and ab = - 1, then (θ - ϕ)$ is equal to

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π4

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Correct option is C

Given that, θ=tan−1⁡a and ϕ=tan−1⁡b and ab=−1 ∴tan⁡θtan⁡ϕ=ab=−1⇒tan⁡θ=−cot⁡ϕ⇒tan⁡θ=tan⁡π2+ϕ⇒θ−ϕ=π2

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If θ=tan−1⁡a,ϕ=tan−1⁡b and ab=−1, then (θ−ϕ) is equal to

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$If θ = \tan^{- 1} a, ϕ = \tan^{- 1} b and ab = - 1, then (θ - ϕ)$ is equal to