If 3tan−1⁡12+3−tan−1⁡1x=tan−1⁡12 then   2021x is equal to

Given equation can be written as3tan−1⁡(2−3)−tan−1⁡1x=tan−1⁡12⇒3π12−tan−1⁡1x=tan−1⁡12⇒tan−1⁡1x=π4−tan−1⁡12Taking tangent on both sides, we get1x=1−121+12⇒x=3