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If 1+tanα1+tan4α=2,α0 ,     π16 then  α=

a
π20
b
π30
c
π40
d
π60

detailed solution

Correct option is A

If α+β=π4 then (1+tanα)(1+tanβ)=2Given 1+tanα1+tan4α=2⇒α+4α=π4⇒α=π20

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