Q.
If tanα2 and tanβ2 are the roots of the equation 8x2−26x+15=0, then cos(α+β)=
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a
−627725
b
627725
c
-1
d
none of these
answer is A.
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Detailed Solution
We have,tanα2+tanβ2=134 and tanα2tanβ2=158tanα2+β2=tanα2+tanβ21−tanα2tanβ2=267Now,cos(α+β)=1−tan2α+β21+tan2α+β2=1−676191+67649=−627725
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