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If $\tan A, \tan B, \tan C$ satisfy the equation $3 \tan^{3} θ - 4 \tan^{2} θ + 3 \tan θ + 1 = 0,$ then $A + B + C =$

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Correct option is B

S1=tan⁡A+tan⁡B+tan⁡C=4/3S2=∑tan⁡Atan⁡B=1,S3=tan⁡Atan⁡Btan⁡C=−1/3tan⁡(A+B+C)=S1−S31−S2→∞⇒A+B+C=π/2

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2023 | www.infinitylearn.com

If tan A, tan B, tan C satisfy the equation 3tan3⁡θ−4tan2⁡θ+3tan⁡θ+1=0, then A + B + C =

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Ready to Test Your Skills?

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If $\tan A, \tan B, \tan C$ satisfy the equation $3 \tan^{3} θ - 4 \tan^{2} θ + 3 \tan θ + 1 = 0,$ then $A + B + C =$