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If $\tan A - \tan B = x and \cot B - \cot A = y,$ then the value of $\cot (A - B)$ is

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x−yxy

1x2+1y2

x+yxy

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detailed solution

Correct option is C

cot⁡(A−B)=cot⁡Acot⁡B+1cot⁡B−cot⁡A=yx+1y=x+yxy

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If tan⁡A−tan⁡B=x and cot⁡B−cot⁡A=y, then the value of cot⁡(A−B) is

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If $\tan A - \tan B = x and \cot B - \cot A = y,$ then the value of $\cot (A - B)$ is