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If $\tan^{- 1} 3 + \tan^{- 1} x = \tan^{- 1} 8, then x =$

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Correct option is B

We have,tan−1⁡3+tan−1⁡x=tan−1⁡8⇒ tan−1⁡x=tan−1⁡8−tan−1⁡3⇒ tan−1⁡x=tan−1⁡8−31+24⇒x=15

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If tan−1⁡3+tan−1⁡x=tan−1⁡8, then x=

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If $\tan^{- 1} 3 + \tan^{- 1} x = \tan^{- 1} 8, then x =$