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If $\tan θ = - 4 / 3$ , then $\sin θ$ is

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Correct option is B

We have, tan⁡θ<0⇒θ lies either in II quadrant or IV quadrant⇒ sin⁡θ>0 or, sin⁡θ<0∴ tan⁡θ=−43⇒sin⁡θ=±45⇒sin⁡θ=45 or, sin⁡θ=−45

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If tan⁡θ=−4/3, then sin θ is

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If $\tan θ = - 4 / 3$ , then $\sin θ$ is