If 5tan⁡θ=4, then 5sin⁡θ−3cos⁡θ5sin⁡θ+2cos⁡θ is equal to

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answer is C.

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Detailed Solution

5tan⁡θ=4 or tan⁡θ=45 Now, 5sin⁡θ−3cos⁡θ5sin⁡θ+2cos⁡θ=5sin⁡θcos⁡θ−35sin⁡θcos⁡θ+2=5tan⁡θ−35tan⁡θ+2=5×45−35×45+2=16

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