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If $\tan^{- 1} x + 2 \cot^{- 1} x = \frac{2 π}{3}, then x =$

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Correct option is B

We have,tan−1⁡x+2cot−1⁡x=2π3⇒tan−1⁡x+2π2−tan−1⁡x=2π3⇒tan−1⁡x=π3⇒x=3

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If tan−1⁡x+2cot−1⁡x=2π3, then x=

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Ready to Test Your Skills?

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If $\tan^{- 1} x + 2 \cot^{- 1} x = \frac{2 π}{3}, then x =$