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If $\int (1 - \tan 3 x)^{2} d x = \frac{1}{2} [\tan 3 x + \log f (x)] + C$ then $f (x)$ is given by

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Correct option is B

∫(1−tan⁡3x)2dx=∫1+tan2⁡3x−2tan⁡3xdx=∫sec2⁡3x−2tan⁡3xdx=tan⁡3x3−23log⁡|sec⁡3x|+C=13tan⁡3x+log⁡cos2⁡3x+C

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If ∫(1−tan⁡3x)2dx=12[tan⁡3x+log⁡f(x)]+C then f(x) is given by

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If $\int (1 - \tan 3 x)^{2} d x = \frac{1}{2} [\tan 3 x + \log f (x)] + C$ then $f (x)$ is given by