If 2tan−1x+sin−12x1+x2 is independent of x, then
x∈[1,∞)∈(−∞,−1)
x∈[−1,1]
x∈(-∞,1]
none of these
We know that
sin−12x1+x2=2tan−1x, if −1≤x≤1π−2tan−1x, if x≥1−π−2tan−1x, if x≤−1
∴ 2tan−1x+sin−12x1+x2=4tan−1x, if −1≤x≤1π, if x≥1−π, if x≤−1
Thus, 2tan−1x+sin−12x1+x2 is independent of x, if
x∈[1,∞) or, x∈(−∞,−1].