If tanx+tan2x+tan3x=tanxtan2xtan3x then value of |sin3x+cos3x| is
tanx+tan2x+tan3x=tanxtan2xtan3x⇒ x+2x+3x=nπ,n∈Z⇒ x=nπ/6,n∈Z |sin3x+cos3x|=1