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Questions  

If tanx2=tany3=tanz5 and  x+y+z=π then the value of tan2x+tan2y+tan2z is 

a
383
b
38
c
114
d
none of these

detailed solution

Correct option is A

x+y+z=π⇒tan⁡x+tan⁡y+tan⁡z=tan⁡ xtan⁡ ytan⁡ z ⇒2k+3k+5k=2k×3k×5k⇒k2=1/3tan2⁡x+tan2⁡y+tan2⁡z=13(4+9+25)=383.

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