If the tangent at P(θ) on the ellipse 16x2+11y2=256touches the circle x2+y2+2x−15=0, then θ−
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a
π6
b
π3
c
2π3
d
5π6
answer is C.
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Detailed Solution
Centre of the circle is (– 1, 0) and radius is 4. Equation of the tangent at P(θ) to the ellipse isx4cos θ+y16/11sin θ=1If this touches the circle, then−cos θ4−1cos2 θ16+sin2 θ256/11=4⇒(cos θ+4)2=256cos2 θ16+11sin2 θ256⇒4cos2 θ−8cos θ−5=0⇒(2cos θ−5)(2cos θ+1)=0⇒cos θ=−1/2⇒θ=2π/3