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If the tangents are drawn to the circlex2+y2=12 at the point where it meets the circle x2+y25x+3y2=0 then the point of intersection of these tangents, is 

a
(6,−6)
b
(6,18/5)
c
(6,−18/5)
d
none of these

detailed solution

Correct option is B

Let (h, k) be the point of intersection of the tangents. Then, the chord of contact of tangents is the common chord of the circles x2+y2=12 and x2+y2−5x+3y−2=0The equation of the common chord is 5x−3y−10=0Also, the equation of the chord of contact ishx+ky−12=0Equations (i) and (ii) represent the same line. Therefore, h5=k−3=−12−10⇒h=6,k=−18/5Hence, the required point is (6,−18/5).

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