If tangents are drawn to the ellipse x2+2y2=2 , then the locus of the midpoint of the intercept made by the tangents between the coordinate axes is
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a
12x2+14y2=1
b
14x2+12y2=1
c
x22+y24=1
d
x24+y22=1
answer is A.
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Detailed Solution
Tangent to ellipsex22+y21=1 at P(2cosθ,sinθ) is given byxcosθ2+ysinθ=1It meets axes at A and B . Let Q(h, k) be midpoint of AB. Using midpoint formula, we haveA≡(2secθ,0) and B≡(0,cosecθ) Hence ,2h=2secθ and 2k=cosecθor 12h2+12k2=1or 12h2+14k2=1or12x2+14y2=1