If the 7th term in the binomial expansion of 3841/3+3lnx9, (x>0) is equal to 729, then x is equal to
e,1/e
2e, 1/2e
e2,e-2
1/e
T7=9C63841/39−6(3lnx)6⇒ 9×8×73×2⋅338433(lnx)6=729⇒ (lnx)6=1⇒ lnx=±1⇒x=e,1/e