Q.

If the 7th term in the binomial expansion of 3841/3+3ln⁡x9, (x>0) is equal to 729, then x is equal to

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a

e,1/e

b

2e, 1/2e

c

e2,e-2

d

1/e

answer is A.

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Detailed Solution

T7=9C63841/39−6(3ln⁡x)6⇒     9×8×73×2⋅338433(ln⁡x)6=729⇒     (ln⁡x)6=1⇒     ln⁡x=±1⇒x=e,1/e
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If the 7th term in the binomial expansion of 3841/3+3ln⁡x9, (x>0) is equal to 729, then x is equal to