Q.
If the 7th term in the binomial expansion of 3841/3+3lnx9, (x>0) is equal to 729, then x is equal to
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a
e,1/e
b
2e, 1/2e
c
e2,e-2
d
1/e
answer is A.
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Detailed Solution
T7=9C63841/39−6(3lnx)6⇒ 9×8×73×2⋅338433(lnx)6=729⇒ (lnx)6=1⇒ lnx=±1⇒x=e,1/e
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