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If the $7$ th term in the binomial expansion of ${(\frac{3}{84^{1 / 3}} + \sqrt{3} \ln x)}^{9}$ , $(x > 0)$ is equal to $729,$ then $x$ is equal to

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Correct option is A

T7=9C63841/39−6(3ln⁡x)6⇒ 9×8×73×2⋅338433(ln⁡x)6=729⇒ (ln⁡x)6=1⇒ ln⁡x=±1⇒x=e,1/e

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If the 7th term in the binomial expansion of 3841/3+3ln⁡x9, (x>0) is equal to 729, then x is equal to

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If the $7$ th term in the binomial expansion of ${(\frac{3}{84^{1 / 3}} + \sqrt{3} \ln x)}^{9}$ , $(x > 0)$ is equal to $729,$ then $x$ is equal to