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If the 6^th term in the expansion of ${(\frac{1}{x^{8 / 3}} + x^{2} \log_{10} x)}^{8}$ is 5600, then x equals

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Correct option is C

It is given that 6th term in the expansion of 1x8/3+x2log10⁡x8 , 5600; therefore, 8C5x2log10x51x8/33=5600 {General term Tr+1=ncrxn-r ar }or 56x10log10⁡x51x8=5600or x2log10⁡x5=100or x2log10⁡x5=102log10⁡105or x=10

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If the 6th term in the expansion of 1x8/3+x2log10⁡x8 is 5600, then x equals

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If the 6^th term in the expansion of ${(\frac{1}{x^{8 / 3}} + x^{2} \log_{10} x)}^{8}$ is 5600, then x equals