If the 6th term in the expansion of 1x8/3+x2log10⁡x8 is 5600, then x equals

It is given that 6th term in the expansion of 1x8/3+x2log10⁡x8 , 5600; therefore, 8C5x2log10x51x8/33=5600  {General term Tr+1=ncrxn-r ar }or 56x10log10⁡x51x8=5600or x2log10⁡x5=100or x2log10⁡x5=102log10⁡105or x=10