If the 6th term from the beginning is equal to the 6th term from the end in the expansion of 21/5+131/5n, then n is equal to

6th term from the beginning       =nC521/5n−5131/55=nC52n/56Also, 6th term from the end         =(n+2−6)=(n−4) th from the beginning         =nCn−521/5n−(n−5)131/5n−5=nC563n/5We are given  nC52n/56=nC563n/5⇒6n/5=62⇒n=10