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If the 6th term from the beginning is equal to the 6th term from the end in the expansion of ${(2^{1 / 5} + \frac{1}{3^{1 / 5}})}^{n},$ then $n$ is equal to

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Correct option is C

6th term from the beginning =nC521/5n−5131/55=nC52n/56Also, 6th term from the end =(n+2−6)=(n−4) th from the beginning =nCn−521/5n−(n−5)131/5n−5=nC563n/5We are given nC52n/56=nC563n/5⇒6n/5=62⇒n=10

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If the 6th term from the beginning is equal to the 6th term from the end in the expansion of 21/5+131/5n, then n is equal to

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If the 6th term from the beginning is equal to the 6th term from the end in the expansion of ${(2^{1 / 5} + \frac{1}{3^{1 / 5}})}^{n},$ then $n$ is equal to