If $$A=3$$ $$20$$ $$1$$ , then A–$$3$$ is

Correct option is 31271−26027

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If $A = [\begin{array}{ll} 3 2 \\ 0 1 \end{array}]$ , then $A^{- 3}$ is

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1271−260−27

127−1−260−27

1271−26027

127−1260−27

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detailed solution

Correct option is C

We have A−1=131−203⇒A−3=1271−2031−2031−203=1271−8091−203=1271−26027

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If A=3 20 1 , then A–3 is

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If $A = [\begin{array}{ll} 3 2 \\ 0 1 \end{array}]$ , then $A^{- 3}$ is