If $$A=221$$−$$102410$$ then $$11A$$−$$1=$$

Correct option is 4−2148−4−5−162

Questions

$If A = [\begin{array}{ccc} 2 & 2 & 1 \\ - 1 & 0 & 2 \\ 4 & 1 & 0 \end{array}] then 11 A^{- 1} =$

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2148−4−5−1−6−2

214845162

−2−1−48−4−5−162

−2148−4−5−162

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detailed solution

Correct option is D

det A=2 (0−2)−2(0−8)+(−1−0)=−4+16−1=1111A−1=AdjA=A11A21A31A12A22A32A13A23A33=−2148−4−5−162

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If A=221−102410 then 11A−1=

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$If A = [\begin{array}{ccc} 2 & 2 & 1 \\ - 1 & 0 & 2 \\ 4 & 1 & 0 \end{array}] then 11 A^{- 1} =$