If A=01−1213321 then A(adjA)A−1A=
600060006
−6000−6000−6
01/6−1/61/31/61/21/21/31/6
none
det A=−12−9−14−3=7−1=6
AAdj AA−1A=AAdj AA−1A=Aadj A=det(A)I=6I