First slide

Applications of determinant

Question

$If A = [\begin{array}{cc} 1 & 3 \\ 2 & - 1 \end{array}] then adj A =$

Moderate

A

$[\begin{matrix} - 1 & - 3 \\ - 2 & 1 \end{matrix}]$
B

$[\begin{matrix} 1 & - 3 \\ - 2 & 1 \end{matrix}]$
C

$[\begin{matrix} 1 & - 3 \\ 2 & 1 \end{matrix}]$
D

$[\begin{matrix} - 1 & - 3 \\ - 2 & - 1 \end{matrix}]$

Solution

$If A = [\begin{array}{ll} a b \\ c d \end{array}] then adj A = [\begin{array}{cc} d & - b \\ - c & a \end{array}]$
$adj A = [\begin{array}{cc} - 1 & - 3 \\ - 2 & 1 \end{array}]$

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